This is a demo task.
Write a function:
function solution(A);
that, given an array A of N integers, returns the smallest positive integer (greater than 0) that does not occur in A.
For example, given A = [1, 3, 6, 4, 1, 2], the function should return 5.
Given A = [1, 2, 3], the function should return 4.
Given A = [−1, −3], the function should return 1.
Write an efficient algorithm for the following assumptions:
function solution(A) {
let maxVal = Math.max(...A);
if (maxVal < 1) return 1;
for (let i = 1; i < maxVal + 1; i++) {
if (!A.includes(i)) return i;
}
return maxVal + 1;
}
function solution(A) {
A.sort((b, a) => a - b);
let maxVal = A[0];
if (maxVal < 1) return 1;
for (let i = 1; i < maxVal + 1; i++) {
if (!A.includes(i)) return i;
}
return maxVal + 1;
}
function solution(A) {
for (i = 1; i < 1000000; i++) {
if (!A.includes(i)) return i;
}
}
function solution(A) {
const set = new Set(A);
let i = 1;
while (set.has(i)) {
i++;
}
return i;
}